Given data d = 22 cm = 0.22 ml = 28 cm = 0.28 mN = 350 rpmWnet = 65 kgDeff = 100 cm = 1 mReff= 0.5 mpm = 3 bar = 300 kPamf = 4 kg/HrCV = 43 MJ = 43000 kJTo Find : ηηIP = ?, BP = ?, ηm = ?, ηbth = ? Now, IP = pm l A N60πIP = 300 × 0.28 × π4 0.22 2 × 35060IP = 18.626 kW Now, πBP = 2π N T60πBP = 2π N Wnet Reff60πBP = 2π × 350 × 65 × 9.81 × 0.560BP = 11.685 kWNow, ηηm = BPIPηηm = 11.685 18.626ηηm = 0.6273ηηm = 62.73 %Now, ηηbth = BP mf 3600 × CV ηηbth = 11.685 4 3600 × 43000 ηηbth = 0.2445ηηbth = 24.45 %