Subjects
Applied Mathematics for Electrical Engineering - 3130908
Complex Variables and Partial Differential Equations - 3130005
Engineering Graphics and Design - 3110013
Basic Electronics - 3110016
Mathematics-II - 3110015
Basic Civil Engineering - 3110004
Physics Group - II - 3110018
Basic Electrical Engineering - 3110005
Basic Mechanical Engineering - 3110006
Programming for Problem Solving - 3110003
Physics Group - I - 3110011
Mathematics-I - 3110014
English - 3110002
Environmental Science - 3110007
Software Engineering - 2160701
Data Structure - 2130702
Database Management Systems - 2130703
Operating System - 2140702
Advanced Java - 2160707
Compiler Design - 2170701
Data Mining And Business Intelligence - 2170715
Information And Network Security - 2170709
Mobile Computing And Wireless Communication - 2170710
Theory Of Computation - 2160704
Semester
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Semester - 5
Semester - 6
Semester - 7
Semester - 8
Basic Mechanical Engineering
(3110006)
BME-3110006
Summer-2019
Question-1c
BE | Semester-
1
Summer-2019
|
04-06-2023
Q1) (c)
7 Marks
Define specific heat at constant volume, constant pressure and adiabatic index. Also derive relationship between specific heats in form of Characteristic gas constant.
Specific heat at Constant volume:
It is defines as the quantity of heat required to raise the temperature of unit mass of the substance by one degree at constant volume.
Specific heat at Constant pressure:
It is defines as the quantity of heat required to raise the temperature of unit mass of the substance by one degree at constant pressure.
Adiabatic index:
It is the ratio of specific heat at constant pressure (C_p ) to the specific heat at constant volume (C_v ).
Mathematically,
γ
γ
C
p
C
v
=
γ
;
γ
=
adiabatic
index
Relationship between specific heats in form of characteristic gas constant:
At constant pressure, from the 1st law of thermodynamics,
Q
1
-
2
=
dU
+
W
1
-
2
For constant pressure process, the heat transferred,
Q
1
-
2
=
mC
p
dT
Change in internal energy is,
dU
=
mC
v
dT
Work done is given by,
W
1
-
2
=
p
dV
Substitute the value of
Q
1
-
2
,
dU
and
W
1
-
2
in above equation, we get
mC
p
dT
=
mC
v
dT
+
pdV
From a characteristic gas equation,
pV
=
mRT
mC
p
dT
=
mC
v
dT
+
mRdT
C
p
=
C
v
+
R
R
=
C
p
-
C
v
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