Here, Incident intensity = I0 Transmitted intensity = I = 4 I0 Thickness = d = 0.5 cm = 5 × 10-3 m Absorption coefficient α= α Now, αII0 = exp -α d α⇒0.4 × I0I0 = exp -α d α⇒ln 0. 4 = - α d α⇒α = - ln 0. 4 d α⇒α = - - 0.916 5 × 10-3 α⇒α = 0.18 × 103 m-1