Applied Mathematics for Electrical Engineering (3130908)

Question-4c ( i )

BE | Semester-3 Winter-2019 | 26-11-2019

Q4) (c ( i ))

The probability that first person hits the target is

P (A) = \frac{3}{4} and P (A) = \frac{1}{4}

The probability that second person hits the target is

P (A) = \frac{2}{3} and P (B) = \frac{1}{3} .

Here, both the events are independent.

Therefore, probability of not hitting the target is,

P (not hitting the target) = P (\bar{A} \cap \bar{B}) = P (\bar{A}) \cdot P (\bar{B})

P (n o t h i t t i n g t h e t a r g e t) = (\frac{1}{4}) (\frac{1}{3})

P (n o t h i t t i n g t h e t a r g e t) = \frac{1}{12}

So, P (hitting the target) = 1 - P (\bar{A}) \cdot P (\bar{B})

S o, P (h i t t i n g t h e t a r g e t) = 1 - \frac{1}{12}

S o, P (h i t t i n g t h e t a r g e t) = \frac{11}{12}