Applied Mathematics for Electrical Engineering (3130908)

BE | Semester-3   Winter-2019 | 26-11-2019

Q3) (c ( i )) 

In producing screws, let A mean “screw too slim” and B “screw too small”. Let P(A)=0.1 and let the conditional probability that a slim screw is also too small be P(B/A)=0.2. What is the probability that the screw that we pick randomly from a lot produced will be both too slim and too short?

Here,
A = Screw is too slim
B = Screw is too small
 
Given that , P(A)=0.1 & P(B/A)=0.2.
 
Then, probability that the screw we pick randomly is both to slim and too short is,
 
P(A∩B)= P(A) P(B⁄A)
 
P(A∩B)=( 0.1 ) ( 0.2 )
 
P(A∩B)=0.02

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