Here, f x = ex2, and a = 0.5 ; b = 1.3 Given that, h = 0.2 x 0.5 0.7 0.9 1.1 1.3 f( x ) 1.2840 1.6323 2.2479 3.3535 5.4195 By Trapezoidal rule, ∫abf x dx = h 2 y0 + y10 + 2 y1 + y2 + y3 + ... ∫abf x dx = 0.2 2 ( 1.2840 + 5.4195 ) + 2 ( 1.6323 + 2.2479 + 3.3535 ) ∫abf x dx = 2.1171