Here, A = Screw is too slim B = Screw is too small Given that , P(A)=0.1 & P(B/A)=0.2. Then, probability that the screw we pick randomly is both to slim and too short is, P(A∩B)= P(A) P(B⁄A) P(A∩B)=( 0.1 ) ( 0.2 ) P(A∩B)=0.02