Subjects
Applied Mathematics for Electrical Engineering - 3130908
Complex Variables and Partial Differential Equations - 3130005
Engineering Graphics and Design - 3110013
Basic Electronics - 3110016
Mathematics-II - 3110015
Basic Civil Engineering - 3110004
Physics Group - II - 3110018
Basic Electrical Engineering - 3110005
Basic Mechanical Engineering - 3110006
Programming for Problem Solving - 3110003
Physics Group - I - 3110011
Mathematics-I - 3110014
English - 3110002
Environmental Science - 3110007
Software Engineering - 2160701
Data Structure - 2130702
Database Management Systems - 2130703
Operating System - 2140702
Advanced Java - 2160707
Compiler Design - 2170701
Data Mining And Business Intelligence - 2170715
Information And Network Security - 2170709
Mobile Computing And Wireless Communication - 2170710
Theory Of Computation - 2160704
Semester
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Semester - 7
Semester - 8
Basic Mechanical Engineering
(3110006)
BME-3110006
Summer-2019
Question-3b-OR
BE | Semester-
1
Summer-2019
|
04-06-2023
Q3) (b)
4 Marks
Prove that the efficiency of Otto cycle is greater than that of Diesel cycle for the same compression ratio.
A comparison of the cycles (Otto, Diesel and Dual) on the p-v and T-s diagrams for the same compression ratio and heat supplied is shown in the Figure.
We know that,
η
η
=
1
-
Heat
rejected
Heat
supplied
Since all the cycles reject their heat at the same specific volume, process line from state 4 to 1, the quantity of heat rejected from each cycle is represented by the appropriate area under the line 4 to 1 on the T-s diagram.
It is seen from the T-s diagram for the same heat input, the heat rejection in Otto is minimum and heat rejection in Diesel cycle is maximum. Consequently, Otto cycle has the highest work output and efficiency. Diesel cycle has the least efficiency.
It is the evident from the above equation that the cycle which has the least heat rejected will have the highest efficiency.
Thus, the efficiency of Otto cycle is greater than that of Diesel cycle for the same compression ratio.
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