Solution of Heat equation: ux, t = ∑n = 1∞ Bn sin nπxL e-n2π2c2tL2 Bn = 2L ∫0L fx sin nπxL dx Bn = 22 ∫02 10 sin nπx2 dx Bn = 10 - cos nπx2nπ202 Bn = 20 nπ - cos nπ +cos 0 = 20 nπ 1 - cos nπ Bn = 20 nπ 1 - -1n Solution: ux, t = ∑n = 1∞ Bn sin nπxL e-n2π2c2tL2 ux, t = ∑n = 1∞ 20 nπ 1 - -1n sin nπx2 e-n2π2c2t4